Prerequisite: calculus, physics
What I love most about parametric, vector, and polar functions.. their graphs are sooo pretty!
Parametric
Recall the basics of parametric functions:
x = f(t)
y = g(t)
(dy/dx) = (dy/dt)(dt/dx)
Personally, I like to use ∆ instead of d for visualization. It appeals much more to a physicist. To step up to second order derivative, this is what you do:
y'' = (d/dx)y' = (dy'/dt)(dt/dx)
Basically y'' is the derivative of y', which can be written in the form (dy'/dt). Then simply do the division divination cancellation hocus pocus~
My calculus AB class at school has not yet done arc length, but here is the parametric equation. I find that it helps to think in terms of ∆:
L = ∫ √ (dx/dt)^2 + (dy/dt)^2 dt [t', t'']
Vector
Having done a load of Newtonian physics the basics are already intuitive, but there are still some new content. The unit vector is a vector of magnitude 1 that points in a direction, given by (v / |v|). Not sure what purpose this serves. Never came across such a thing.
Velocity and acceleration are just derivatives of one another, yet they can be separated into components. That means, so can an integral:
displacement = < ∫ vx(t) dt , ∫ vy(t) dt > [a, b]
distance = ∫ |v(t)| dt = ∫ √(vx(t))^2 + (vy(t))^2 dt [a, b]
in which vx(t) is the x component of v(t), and vy(t) the y component.
Polar
Never knew about polar coordinates before.. but I love the curves! Polar functions have fancy names for the origin and x axis, called the pole and initial ray respectively, but they are the same thing. I suppose the naming makes sense since polar functions only need one point to start with and one axis to label radius lengths on. Polar functions are based on:
r = f(θ)
where r is the radius spanning out from the pole, and θ is the angle away from the initial ray.
Rectangular conversion converts polar coordinates into "ordinary" coordinates, which is essentially just taking the x and y position component of the radius.
x = rcosθ
y = rsinθ
and you can call these useful identities:
r^2 = x^2 + y^2
tanθ = y/x
You can also split a polar function into its components to make a parametric function:
x = rcosθ = f(θ)cosθ
y = rsinθ = f(θ)sinθ
This parametrized polar function can then undergo division divination cancellation hocus pocus as well~
(dy/dx) = (dy/dθ)(dθ/dx)
As for integrals, it is not so obvious. Start with the original formula for a sector's area:
A = (1/2)(r^2)θ
Make it differential. It looks funny at first but if you think in terms of ∆, it makes more sense.
dA = (1/2)(r^2)dθ
And of course if you take the integral of this, you get the sector area.
A = ∫ (1/2)(r^2) dθ [a, b]
Really, go look at some pictures of polar graphs. They are sooo pretty > <